EVALUATING THE EQUILIBRIUM CONSTANT FOR THE REACTION OF IRON (III) ION WITH THIOCYANATE ION

PLEASE TYPE A CHEMISTRY LAB REPORT ON THE FOLLOWING LAB :

LAB PROCEDURE & DATA SHEETS ARE ATTACHED BELOW TO THIS POST. PLEASE REFER BACK TO LAB MANUAL IF YOU ARE CONFUSED OR UNSURE ON WHAT TO DO. PLEASE COMPLETE THE DATA SHEET ALONG WITH CALCULATIONS. (SHOW ALL WORK)

Data - any basis and observations you capture (weighings, volumes, results of tests etc.). Write all basis promptly into your notebook, not your lab manual, as you capture it. Tabulate basis where withhold.

Report Sheets - the completed Basis and Report Sheets from the lab manual.

Calculations - If there are calculations you must explicitly, and logically, appearance all your established to get generous merit.

Discussion - Decipher your results, referring to the chemistry speculation where withhold. Did the basis adapt to what was expected? What does it appearance in homogeneity to the test? If the results are not what was expected decipher why. Possible sources of falsity (admire testal falsity in numerical results). You do not deficiency to exculpation the Post Lab Questions in the manual unless instructed.

ONLY PART II & III WERE CONDUCTED IN THIS LAB

PART 2 RESULTS    ABS= ABSORANCE 

S1 

ABS: 0.005

WAVE LENGTH: 388.00 nm

S2 

ABS: 0.780

WAVE LENGTH: 446.40 nm

S3

ABS: 1.970

WAVE LENGTH: 436.80 nm

S4

ABS: 2.024

WAVE LENGTH: 436.80nm

S5

ABS: 2.056

WAVE LENGTH: 426.30nm

PART 3 RESULTS

E1 (BLANK)

ABS: 0.001

WAVE LENGTH: 442.8nm

E2

ABS: 1.613

WAVE LENGTH: 446.40

E3

ABS: 1.960

WAVE LENGTH:423.70 nm

E4

ABS: 1.966

WAVE LENGTH: 426.30nm

E5

ABS: 1.971

WAVE LENGTH:436.80 nm

E6

ABS: 1.971

WAVE LENGTH: 436.80 nm

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