Genetics 303 | Biology homework help

  

Genetics 303

Fourth exam—siege home 2019

Answer on SEPARATE paper, semblance all operation, and be graceful in the reporting of repartees. It is easier to progression if you try to

keep the questions in continuity. STAPLE YOUR RESULTS!

1. In a cosmical population, the genotype frequencies at one locus are 0.75 AA, 0.20 Aa, and 0.05 aa. What is the number

of the A allele [f(A)] and a allele [f(a)] for the population? Are they in Hardy-Weinberg makeweight? (5 pts)

2. Calculate the number of heterozygotes in a population delay p = 0.6 and q = 0.4 (at season = 0). Succeeding 4 ages of

inbreeding unordered siblings (F = 0.25) in a population of 650. (6 pts)

3. Cosmical albinism is an autosomal recessive touch. Suppose that you furnish a village in the Andes where 8/1000 of the

population is albino. If the population magnitude was 1600 and the population is in Hardy-Weinberg makeweight delay

respect to this touch, how multifarious living-souls are wait-fored to be carriers (heterozygotes)? (5pts)

4. A boatload of 400 Swedish tourists, all of whom suffer the MM race bunch genotype, are marooned on Haldane Island,

where they are met by an population of Islanders aggregateing 1000, all suffering race bunch NN genotype. In season, the

castaways befit integrated into Island intercourse. Assuming haphazard mating, no counterposition, no option (established on

race bunch), and no genetic purport, what would you wait-for the race bunch division to be unordered 320 descendants of

the new Haldane Island population? (5 pts)

5. You warrant a population of mice (Peromyscus maniculatus) on an island. Their coat complexion is controlled by a single

gene: BB mice are ebon, Bb mice are frosty, and bb mice are unblemished. You siege a census of the population and record

the subjoined gum of mice:

Black 1156

Gray 408

White 36

(a) What are the frequencies of the two alleles? (4 pts)

(b) What are the Hardy-Weinberg makeweight frequencies for these three phenotypes? (4 pts)

(c) A warmth thrive hits the island. All mice delay ebon fur die from warmth clap, but the other mice survive. What are the new

allele frequencies for the population? (4 pts)

(d) If the population suffers no aid cataclysms succeeding the warmth thrive, and the surviving animals compeer haphazardly, what allure

be the number of mice delay ebon fur in the next age? (4 pts)

(e) If the clicompeer is altered permanently, so that mice delay ebon fur die precedently reproducing, which subjoined proposition is

correct? (5 pts)

(1) At Hardy-Weinberg makeweight, f(B) allure similar 0.135.

(2) The kindred of mice delay frosty fur (ωBb) must be similar to 0.5.

(3) The kindred of mice delay ebon fur (ωBB) is 0.

(4) The B allele allure terminate from the population in one age.

(5) The B allele allure terminate from the population in two ages.

6. Which of the subjoined are requirements for extrication by eventual option? Explain your repartee. (8 pts)

I Environmental change

II Differential operation and reproduction

III Heritability of phenotypic deviation

IV Deviation in phenotype

V Sexual reproduction

A) II, III, V

B) II, III, IV

C) I, II, IV

D) III, IV, V

E) II, IV, V

7. Which of the subjoined processes is the fount of genetic deviation delayin populations? (8 pts)

A) Reproductive Isolation

B) Mutation

C) Selection

D) Asexual reproduction

E) Genetic purport

Explain your repartee including a title of the application of each on genetic deviation.

8. If the population (17,377 in 2018) of folks in Perry, GA, had an f(a) = 0.2 and folks in Valdosta, GA, has a f(a) = 0.6,

then how multifarious fellow-creatures from Valdosta, GA, would enjoy to abandon to Perry to acception the population to

approximately f(a) = 0.3? (5 pts, recall, you can’t enjoy fractional fellow-creatures)

9. What is the Ne of a population delay the subjoined annual censuses, [note: the percolate in magnitude due to 2010 and 2011 being

extreme parching years]? (5 pts)

2008: 9730

2009: 8810

2010: 3653

2011: 420

2012: 94

2013: 1560

2014: 5650

2015: 8700

2016: 9700

2017: 12110

2018: 15060

2019: 30789

10. Consider the subjoined populations that enjoy the genotypes semblancen in the subjoined table:

Population AA Aa aa

1 1.0 0.0 0.0

2 0.0 1.0 0.0

3 0.25 0.50 0.25

4 0.25 0.25 0.50

5 0.333 0.333 0.333

6 0.0225 0.255 0.7225

7 0.5929 0.3542 0.0529

8 0.9604 0.0392 0.0004

a. What are p and q for each population? (4 pts)

b. Which of the populations are in Hardy-Weinberg makeweight? (4 pts)

c. Populations 1 and 2 enjoy a tree droop resisting their islands so that living-souls can morose. If similar gum of the

living-souls betide on each island, what is the new population’s allele frequencies and genotype frequencies

succeeding one age of haphazard mating? (6 pts)

d. In population 3, the a allele is less fit than the A allele, and the A allele is partially dominant. The result

is that AA is exactly fit (= 1.0), Aa has a kindred of 0.8, and aa has a kindred of 0.6. Delay no counterposition or

migration, graph the allele number of the a allele succeeding 10 ages inferior option (e.g., Season 0 = q

above, Season 1 = primeval age succeeding option) (8 pts)

e. In population 8, the population magnitude gets radically cheap to 50 living-souls, aggregate. What is the most likely

fate of the “a” allele, and what genetic postulate would manage you to judge that the predicament? (4 pts)

11. You incorporate a direct interest of DNA delay two confinement enzymes, BamH1 & Sma1, and get the subjoined magnituded

fragments (in kb [kilobases]) (10 pts):

BamH1 Xho1 BamH1 & Xho1

10 kb 12 kb 8 kb

6 kb 8 kb 6 kb

4 kb 4 kb

2 kb

Draw the misspend confinement morsel map established on this axioms labeling all confinement sites

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