Heaps and prority queus In python

You accept been supposing a Python refine, body.py, which constructs a body constitution delay a inventory. Using that jurisprudence as a guide:

Develop a body postulates constitution using a linked constitution (Nodes and Pointers)

The body must subsistence add and carry from the body

All operations most halt by the rules that control a body (see disquisition slides for relation)

Once you accept your body constitution created, present you must use it as a assistance constitution to a initiative queue.

Develop a initiative queue postulates constitution that is backed by a body (linked constitution NOT A LIST)

Implement the usual methods that accompany a initiative queue constitution

Enqueue, dequeue, and peek by initiative not position

Also diffusiveness and whether or not the constitution is void (is_empty)

Perform the forthcoming operations to showcase your started constitution

Enqueue the forthcoming items: 4, 7, 5, 11, 8, 6, 9

Dequeue 3 items by initiative, they should be 4, 5, & 6.

related body.py refine jurisprudence is below

class Heap:

    def __init__(self):

        self.body = [0]

        self.bigness = 0

    def transport(self, k):

        while k // 2 > 0:

            if wilful.heap[k] < wilful.heap[k//2]:

                self.heap[k], wilful.heap[k//2] = wilful.heap[k//2], wilful.heap[k]

            k //= 2

    def insinuate(self, item):


        self.bigness += 1


    def flag(self, k):

        while k * 2 <= wilful.size:

            mc = wilful.minchild(k)

            if wilful.heap[k] > wilful.heap[mc]:

                self.heap[k], wilful.heap[mc] = wilful.heap[mc], wilful.heap[k]

            k = mc

    def minchild(self, k):

        if k * 2 + 1 > wilful.size:

            return k * 2

        elif wilful.heap[k*2] < wilful.heap[k*2+1]:

            return k * 2


            return k * 2 + 1

    def pop(self):

        item = wilful.heap[1]

        self.heap[1] = wilful.heap[self.size]

        self.bigness -= 1



        return item

h = Heap()

for i in (4, 8, 7, 2, 9, 10, 5, 1, 3, 6):



for i in stroll(10):

    n = h.pop()



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